# David Saavedra Mr. Ferge Physics PAP 11 December

David SaavedraMr.

FergePhysics PAP11 December 2017PhysicsTerm Paper            SCIENCE! “The intellectual andpractical activity encompassing the systematic study of the structure behaviorof the physical and natural world through observation and experiment.” The very definition of science covers all the questions forwhy we do what we do in any science class. In the name of science is why we doour projects, assignments, labs and this term paper. Physics being just one of the branches of science alsocategorizes into more and separate sub-categories ranging from simple non-air resistant classical mechanics to mind-blowing high energy/particle nuclear physics. This detailed explanation is the introduction of how all theconcepts of physics I’velearned this past semester should not just be applied in one real-world example because physics is a part of every being andobject in this world. Nevertheless, I willcover an in-depth explanation on projectile motion with examples and asimplification of this concept.             Furthermore, to understand and learnthe basis of projectile motion, onemust start from the beginning such as learning how to calculate various typesof motion on a strictly linear direction like we did so on our first real-lifeworld based project. Throughoutour course this past semester the projects had begun fairly simple.

We started with incorporating the basics ofunderstanding how some formulas work and how one would calculate to solveacceleration,velocity, force and find time of an object or body inproblem. Our first project “Car accident” involvedthe use of freefall motion. In thisproject, we were tasked with finding out if there was an attempted murder upona person or if it was an accident depending on the increases in acceleration ofthe car. With only the given times of when the carpassed specific points we needed to find out if the car accelerated at acertain point to the point of the impact. Thisproject lead to the answer that this was attempted murder through calculatinghow long it took from one point to another and other equations that measuredthe amount of force behind the car.             Freefall motion being the startingpoint on how to calculate factors such as acceleration, time, distance/displacement, velocity/speed and force of a projectile/object.

It is also very important to understand whatthese factors mean as oppose to how they would be used to find out whatever isneeded to be solved. Tobegin with understanding how these factors need to be looked at in a problem, at times direction and magnitude areincluded. Speed itself is a quantity known as a scalarquantity. Speed itself has no direction, for example; when a problem mentions anobject going at a speed of 20mph south the factor is now looked at velocity. Velocity builds over time within the givedistance and however long it takes to reach said given point in problem.

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Newton’s Laws of motion may not havebeen the original basis of projectile motion, but they did give it a comprehensiblebasis to follow. Projectile motion is in acategory of the area of physics known as classical mechanics. Projectilemotion unlike freefall motion is nonlinear motion that occurs along a curvedpath or a parabola. Thiscurve is composed of two components being constant velocity in a horizontalmotion and accelerated vertical motion. Theseboth components of motion are independent in general amongst projectile motionmeaning that within their place among a linear line horizontal velocity is thex-component and vertical acceleration is the y-component.

Another between freefall and projectile isthe dimensions. Freefallis one dimension and projectile is two dimension do to being non-linear as wellwith the fact that within projectile problems the path is a parabola.            Now either curved or non-curved, freefall or non-freefall gravity will alwaysbe the acceleration for both. Projectilemotion is really just freefall motion with initial horizontal velocity do tobeing thrown,launched or any of that sort at a specific degree. The problems you would see for projectile motion testsor assignments would typically ask you to find the distance reached by theprojectile based on the force of Newton’s behind it and the degree at which itwas launched or it would ask you what the amount of velocity/speed it had uponimpact of when it landed. Findingthe height and range is also asked as a part of projectile equations. This is areal-life example asking what the measured speed should be of a cannonball landingon the ground. Acannonball is launched from the ground at an angle of 30 degrees above thehorizontal and a speed of 30m/s.

(Neglecting air resistance) what speed willthe ball be at when it lands? This problem is a simple one in this area ofprojectile motion. To findthis all that is needed is the given speed 30m/s. With neglected air resistance and the given degree, thespeed upon landing would be 30m/s. Butequations as simple as this do not stop here.             Another way projectile motion couldbe calculated is through kinematic equations. These formulas can be utilized for anymotion from constant velocity motion which is an acceleration of 0 m/s/s or aconstant acceleration motion. They can never be used over any time periodduring which the acceleration is changing.

Each of the kinematic equations include four variableswhich are distance, acceleration, velocity and time. Now a step by step toexpand on kinematics, finding the height and range in a projectile problem:First step as always you receive your given values. Then Split velocity in horizontal and verticalcomponents. Then begin with the constant of the separated components you willfind the final height with the constant. You begin by taking your acceleration,your constant and your changing range which will then translates to a change inrange equals your constant velocity and changing time.

Next step is to check ifa change in time is found in range, let’s say there was. From there youtransfer to the direction of range which then will equal to your final height.            Nowusing the same method’s, you will now use your vertical component to find yourfinal range.

Begin with noting down your acceleration is 9.8 m/s^2. Your velocity on this side of the problem is changing instead of being constant.This then means that change in height equals velocity, change in time plus ½ 9.8m/s^2 and change in time squared. From here on you cannot find yourrange using a change in time. So, you calculate your change in time and heightwhich then equals your range