David Saavedra

Mr. Ferge

Physics PAP

11 December 2017

Physics

Term Paper

SCIENCE! “The intellectual and

practical activity encompassing the systematic study of the structure behavior

of the physical and natural world through observation and experiment.” The very definition of science covers all the questions for

why we do what we do in any science class. In the name of science is why we do

our projects, assignments, labs and this term paper. Physics being just one of the branches of science also

categorizes into more and separate sub-categories ranging from simple non-air resistant classical mechanics to mind-blowing high energy/particle nuclear physics. This detailed explanation is the introduction of how all the

concepts of physics I’ve

learned this past semester should not just be applied in one real-world example because physics is a part of every being and

object in this world. Nevertheless, I will

cover an in-depth explanation on projectile motion with examples and a

simplification of this concept.

Furthermore, to understand and learn

the basis of projectile motion, one

must start from the beginning such as learning how to calculate various types

of motion on a strictly linear direction like we did so on our first real-life

world based project. Throughout

our course this past semester the projects had begun fairly simple. We started with incorporating the basics of

understanding how some formulas work and how one would calculate to solve

acceleration,

velocity, force and find time of an object or body in

problem. Our first project “Car accident” involved

the use of freefall motion. In this

project, we were tasked with finding out if there was an attempted murder upon

a person or if it was an accident depending on the increases in acceleration of

the car. With only the given times of when the car

passed specific points we needed to find out if the car accelerated at a

certain point to the point of the impact. This

project lead to the answer that this was attempted murder through calculating

how long it took from one point to another and other equations that measured

the amount of force behind the car.

Freefall motion being the starting

point on how to calculate factors such as acceleration, time, distance/displacement, velocity/speed and force of a projectile/object. It is also very important to understand what

these factors mean as oppose to how they would be used to find out whatever is

needed to be solved. To

begin with understanding how these factors need to be looked at in a problem, at times direction and magnitude are

included. Speed itself is a quantity known as a scalar

quantity. Speed itself has no direction, for example; when a problem mentions an

object going at a speed of 20mph south the factor is now looked at velocity. Velocity builds over time within the give

distance and however long it takes to reach said given point in problem.

Newton’s Laws of motion may not have

been the original basis of projectile motion, but they did give it a comprehensible

basis to follow. Projectile motion is in a

category of the area of physics known as classical mechanics. Projectile

motion unlike freefall motion is nonlinear motion that occurs along a curved

path or a parabola. This

curve is composed of two components being constant velocity in a horizontal

motion and accelerated vertical motion. These

both components of motion are independent in general amongst projectile motion

meaning that within their place among a linear line horizontal velocity is the

x-component and vertical acceleration is the y-component. Another between freefall and projectile is

the dimensions. Freefall

is one dimension and projectile is two dimension do to being non-linear as well

with the fact that within projectile problems the path is a parabola.

Now either curved or non-curved, freefall or non-freefall gravity will always

be the acceleration for both. Projectile

motion is really just freefall motion with initial horizontal velocity do to

being thrown,

launched or any of that sort at a specific degree. The problems you would see for projectile motion tests

or assignments would typically ask you to find the distance reached by the

projectile based on the force of Newton’s behind it and the degree at which it

was launched or it would ask you what the amount of velocity/speed it had upon

impact of when it landed. Finding

the height and range is also asked as a part of projectile equations. This is a

real-life example asking what the measured speed should be of a cannonball landing

on the ground. A

cannonball is launched from the ground at an angle of 30 degrees above the

horizontal and a speed of 30m/s. (Neglecting air resistance) what speed will

the ball be at when it lands? This problem is a simple one in this area of

projectile motion. To find

this all that is needed is the given speed 30m/s. With neglected air resistance and the given degree, the

speed upon landing would be 30m/s. But

equations as simple as this do not stop here.

Another way projectile motion could

be calculated is through kinematic equations. These formulas can be utilized for any

motion from constant velocity motion which is an acceleration of 0 m/s/s or a

constant acceleration motion. They can never be used over any time period

during which the acceleration is changing. Each of the kinematic equations include four variables

which are distance, acceleration, velocity and time. Now a step by step to

expand on kinematics, finding the height and range in a projectile problem:

First step as always you receive your given values. Then Split velocity in horizontal and vertical

components. Then begin with the constant of the separated components you will

find the final height with the constant. You begin by taking your acceleration,

your constant and your changing range which will then translates to a change in

range equals your constant velocity and changing time. Next step is to check if

a change in time is found in range, let’s say there was. From there you

transfer to the direction of range which then will equal to your final height.

Now

using the same method’s, you will now use your vertical component to find your

final range. Begin with noting down your acceleration is 9.8 m/s^2. Your velocity on this side of the problem is changing instead of being constant.

This then means that change in height equals velocity, change in time plus ½ 9.8m/s^2 and change in time squared. From here on you cannot find your

range using a change in time. So, you calculate your change in time and height

which then equals your range