David Saavedra Mr. Ferge Physics PAP 11 December

David Saavedra

Mr. Ferge

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Physics PAP

11 December 2017

Physics
Term Paper

            SCIENCE! “The intellectual and
practical activity encompassing the systematic study of the structure behavior
of the physical and natural world through observation and experiment.” The very definition of science covers all the questions for
why we do what we do in any science class. In the name of science is why we do
our projects, assignments, labs and this term paper. Physics being just one of the branches of science also
categorizes into more and separate sub-categories ranging from simple non-air resistant classical mechanics to mind-blowing high energy/particle nuclear physics. This detailed explanation is the introduction of how all the
concepts of physics I’ve
learned this past semester should not just be applied in one real-world example because physics is a part of every being and
object in this world. Nevertheless, I will
cover an in-depth explanation on projectile motion with examples and a
simplification of this concept.

            Furthermore, to understand and learn
the basis of projectile motion, one
must start from the beginning such as learning how to calculate various types
of motion on a strictly linear direction like we did so on our first real-life
world based project. Throughout
our course this past semester the projects had begun fairly simple. We started with incorporating the basics of
understanding how some formulas work and how one would calculate to solve
acceleration,
velocity, force and find time of an object or body in
problem. Our first project “Car accident” involved
the use of freefall motion. In this
project, we were tasked with finding out if there was an attempted murder upon
a person or if it was an accident depending on the increases in acceleration of
the car. With only the given times of when the car
passed specific points we needed to find out if the car accelerated at a
certain point to the point of the impact. This
project lead to the answer that this was attempted murder through calculating
how long it took from one point to another and other equations that measured
the amount of force behind the car.

            Freefall motion being the starting
point on how to calculate factors such as acceleration, time, distance/displacement, velocity/speed and force of a projectile/object. It is also very important to understand what
these factors mean as oppose to how they would be used to find out whatever is
needed to be solved. To
begin with understanding how these factors need to be looked at in a problem, at times direction and magnitude are
included. Speed itself is a quantity known as a scalar
quantity. Speed itself has no direction, for example; when a problem mentions an
object going at a speed of 20mph south the factor is now looked at velocity. Velocity builds over time within the give
distance and however long it takes to reach said given point in problem.

            Newton’s Laws of motion may not have
been the original basis of projectile motion, but they did give it a comprehensible
basis to follow. Projectile motion is in a
category of the area of physics known as classical mechanics. Projectile
motion unlike freefall motion is nonlinear motion that occurs along a curved
path or a parabola. This
curve is composed of two components being constant velocity in a horizontal
motion and accelerated vertical motion. These
both components of motion are independent in general amongst projectile motion
meaning that within their place among a linear line horizontal velocity is the
x-component and vertical acceleration is the y-component. Another between freefall and projectile is
the dimensions. Freefall
is one dimension and projectile is two dimension do to being non-linear as well
with the fact that within projectile problems the path is a parabola.

            Now either curved or non-curved, freefall or non-freefall gravity will always
be the acceleration for both. Projectile
motion is really just freefall motion with initial horizontal velocity do to
being thrown,
launched or any of that sort at a specific degree. The problems you would see for projectile motion tests
or assignments would typically ask you to find the distance reached by the
projectile based on the force of Newton’s behind it and the degree at which it
was launched or it would ask you what the amount of velocity/speed it had upon
impact of when it landed. Finding
the height and range is also asked as a part of projectile equations. This is a
real-life example asking what the measured speed should be of a cannonball landing
on the ground. A
cannonball is launched from the ground at an angle of 30 degrees above the
horizontal and a speed of 30m/s. (Neglecting air resistance) what speed will
the ball be at when it lands? This problem is a simple one in this area of
projectile motion. To find
this all that is needed is the given speed 30m/s. With neglected air resistance and the given degree, the
speed upon landing would be 30m/s. But
equations as simple as this do not stop here.

            Another way projectile motion could
be calculated is through kinematic equations. These formulas can be utilized for any
motion from constant velocity motion which is an acceleration of 0 m/s/s or a
constant acceleration motion. They can never be used over any time period
during which the acceleration is changing. Each of the kinematic equations include four variables
which are distance, acceleration, velocity and time. Now a step by step to
expand on kinematics, finding the height and range in a projectile problem:
First step as always you receive your given values. Then Split velocity in horizontal and vertical
components. Then begin with the constant of the separated components you will
find the final height with the constant. You begin by taking your acceleration,
your constant and your changing range which will then translates to a change in
range equals your constant velocity and changing time. Next step is to check if
a change in time is found in range, let’s say there was. From there you
transfer to the direction of range which then will equal to your final height.

            Now
using the same method’s, you will now use your vertical component to find your
final range. Begin with noting down your acceleration is 9.8 m/s^2. Your velocity on this side of the problem is changing instead of being constant.

This then means that change in height equals velocity, change in time plus ½ 9.8m/s^2 and change in time squared. From here on you cannot find your
range using a change in time. So, you calculate your change in time and height
which then equals your range